AP EAMCET · Maths · Quadratic Equation
All the values of \(k\) such that the quadratic expression \(2 k x^2-(4 k+1) x+2\) is negative for exactly three integral vaules of \(x\), lie in the interval
- A \(\left[\frac{1}{12}, \frac{1}{10}\right)\)
- B \(\left(\frac{1}{6}, \frac{1}{5}\right)\)
- C \([-1,2)\)
- D \([2,6)\)
Answer & Solution
Correct Answer
(A) \(\left[\frac{1}{12}, \frac{1}{10}\right)\)
Step-by-step Solution
Detailed explanation
For \(2 k x^2-(4 k+1) x+2 0 \Rightarrow k > 0\). Roots of \(2 k x^2-(4 k+1) x+2 = 0\) are \(x = \frac{(4k+1) \pm \sqrt{(4k-1)^2}}{4k} = \frac{4k+1 \pm |4k-1|}{4k}\). Case 1: \(k \ge \frac{1}{4}\). Roots are \(\frac{1}{2k}\) and \(2\). The inequality \(f(x) Since…
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