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AP EAMCET · Maths · Permutation Combination

If all possible 4 digit numbers are formed by choosing 4 different digits from the given digits \(1,2,3,5,8\) then, the sum of all such 4 digit numbers is

  1. A \(199980\)
  2. B \(999990\)
  3. C \(506616\)
  4. D \(479952\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(506616\)

Step-by-step Solution

Detailed explanation

\(S = 1+2+3+5+8 = 19\) \(N_{each\_digit} = P(5-1, 4-1) = P(4,3) = 24\) \(Sum = S \times N_{each\_digit} \times (1000+100+10+1)\) \(Sum = 19 \times 24 \times 1111\) \(Sum = 456 \times 1111\) \(Sum = 506616\)
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