AP EAMCET · Chemistry · s Block Elements
Calcium phosphide reacts with water to form \(\mathrm{Ca}(\mathrm{OH})_2\) and \(X\). When \(X\) is passed into \(\mathrm{CuSO}_4\) solution. \(Y\) and \(\mathrm{H}_2 \mathrm{SO}_4\) are formed. What is \(Y\) ?
- A \(\left[\mathrm{Cu}\left(\mathrm{PH}_3\right)_4\right]^{2 *}\)
- B \(\left[\mathrm{Cu}\left(\mathrm{PH}_3\right)_6\right]^{2+}\)
- C \(\mathrm{Cu}_3 \mathrm{P}_2\)
- D \(\mathrm{CuHPO}_4\)
Answer & Solution
Correct Answer
(C) \(\mathrm{Cu}_3 \mathrm{P}_2\)
Step-by-step Solution
Detailed explanation
Calcium phosphide reacts with water to form calcium hydroxide and phosphine.…
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