AP EAMCET · Maths · Probability
A random variable \(X\) has the probability distribution
\(\begin{array}{lllllll} \hline X=x_i & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline P\left(X=x_i\right) & 0.2 & 0.3 & 0.12 & 0.1 & 0.2 & 0.08 \\ \hline \end{array}\)
If \(A=\left\{x_i / x_i\right.\) is a prime number}, \(B=\left\{x_i / x_i < 4\right\}\) are two events, then \(P(A \cup B)=\)
- A 0.31
- B 0.62
- C 0.82
- D 0.41
Answer & Solution
Correct Answer
(C) 0.82
Step-by-step Solution
Detailed explanation
The given probability distribution for random variable \(x\) \(\begin{array}{lllllll} \hline x=x_i & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline P\left(X=x_i\right) & 0.2 & 0.3 & 0.12 & 0.1 & 0.2 & 0.08 \\ \hline \end{array}\) and two events \(A=\left\{x_i \mid x_i\right.\) is a prime…
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