AP EAMCET · Maths · Straight Lines
The point to which the origin should be shifted so that the equation \(y^2-6 y-4 x+13=0\) is transformed to the form \(y^2+A x=0\) is
- A \((3,1)\)
- B \((-1,-1)\)
- C \((1,3)\)
- D \((-1,3)\)
Answer & Solution
Correct Answer
(D) \((-1,3)\)
Step-by-step Solution
Detailed explanation
Given equation is \(\begin{aligned} y^2-6 y-4 x+13 & =0 \Rightarrow(y-3)^2=4(x-1) \\ \Rightarrow \quad(y-3)^2-4(x-1) & =0 \end{aligned}\) By analysis of above form, it we shift the origin to \((-1,3)\), then it transformed to the \(y^2+4 x=0\). Hence, option (c) is correct.
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