AP EAMCET · Maths · Three Dimensional Geometry
A plane passes through \((2,3,-1)\) and is perpendicular to the line having direction ratios \(3,-4,7\). The perpendicular distance from the origin to this plane is
- A \(\frac{3}{\sqrt{74}}\)
- B \(\frac{5}{\sqrt{74}}\)
- C \(\frac{6}{\sqrt{74}}\)
- D \(\frac{13}{\sqrt{74}}\)
Answer & Solution
Correct Answer
(D) \(\frac{13}{\sqrt{74}}\)
Step-by-step Solution
Detailed explanation
The equation of the plane passes through the point \((2,3,-1)\) is where \(a, b, c\) are the direction ratio of the normal to the plane. Also, given the plane is perpendicular to the line whose direction ratio is \((3,-4,7)\). So, that line and the normal of the plane are…
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