AP EAMCET · Maths · Heights and Distances
A man \(2 \mathrm{~m}\) tall, walks at the rate of \(1 \frac{2}{3} \mathrm{~m} / \mathrm{s}\) towards a street light which is \(5 \frac{1}{3} \mathrm{~m}\) above the ground. The rate at which the length of his shadow is changing when he is \(3 \frac{1}{3} \mathrm{~m}\) away from the base of the light is ____
- A \(-1 \mathrm{~m} / \mathrm{s}^{-1}\)
- B \(2 \mathrm{~m} / \mathrm{s}\)
- C \(-2 \mathrm{~m} / \mathrm{s}\)
- D \(1 \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(-1 \mathrm{~m} / \mathrm{s}^{-1}\)
Step-by-step Solution
Detailed explanation
\(A B=\) street light, \(C=\) Man. From \(\triangle A B E\) and \(\triangle D C E\),…
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