AP EAMCET · Chemistry · Redox Reactions
Find the equivalent weight of \(\mathrm{MnO}_4^{-}\)for acid medium reactions. (Atomic weight of \(\mathrm{Mn}=55\), Atomic weight of \(\mathrm{O}=16\) )
- A 118.93
- B 23.78
- C 64
- D 54.93
Answer & Solution
Correct Answer
(B) 23.78
Step-by-step Solution
Detailed explanation
In acidic medium \(\mathrm{Mn}^{7+} \longrightarrow \mathrm{Mn}^{2+}\) Therefore, \(n\) factor \((n)=5\) \(\text {Equivalent weight }=\frac{\text { Weight } \mathrm{MnO}_4^{-}}{n \text { - factor }}=\frac{119}{5}=23.8\) Hence, the correct option is (2).
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