AP EAMCET · Maths · Probability
A college student has to appear for two examinations A and B. The probabilities that the student passes in A and B are \(\frac{2}{3}\) and \(\frac{3}{4}\) respectively. If it is known that the student passes at least one among the two examinations, then the probability that the student will pass both the examinations is
- A \(\frac{1}{6}\)
- B \(\frac{1}{2}\)
- C \(\frac{1}{3}\)
- D \(\frac{6}{11}\)
Answer & Solution
Correct Answer
(D) \(\frac{6}{11}\)
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