AP EAMCET · Maths · Circle
A circle passing through the point \((1,0)\) makes an intercept of length 4 units on X -axis and an intercept of length \(2 \sqrt{11}\) units on Y - axis. If the centre of the circle lies in the fourth quadrant, then the radius of the circle is
- A \(4 \sqrt{5}\)
- B \(3\)
- C \(2 \sqrt{5}\)
- D \(5\)
Answer & Solution
Correct Answer
(C) \(2 \sqrt{5}\)
Step-by-step Solution
Detailed explanation
Let the centre of the circle be \((h,k)\) and the radius be \(r\). X-intercept: \(2\sqrt{r^2 - k^2} = 4 \Rightarrow r^2 - k^2 = 4\). Y-intercept: \(2\sqrt{r^2 - h^2} = 2\sqrt{11} \Rightarrow r^2 - h^2 = 11\). Circle passes through \((1,0)\):…
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