AP EAMCET · Maths · Probability
A and B throw a pair of dice alternately and they note the sum of the numbers appearing on the dice. A wins if he throws 6 before B throws 7 and B wins if he throws 7 before \(A\) throws 6 . If \(A\) begins, the probability of his winning is
- A \(\frac{15}{61}\)
- B \(\frac{21}{61}\)
- C \(\frac{30}{61}\)
- D \(\frac{36}{61}\)
Answer & Solution
Correct Answer
(C) \(\frac{30}{61}\)
Step-by-step Solution
Detailed explanation
For sum 6 possible combinations are \((1,5),(5,1)\), \(\begin{aligned} & (2,4),(4,2),(3,3) \\ & P(\text { sum } 6)=\frac{5}{36} \end{aligned}\) For sum 7 possible combinations are \((1,6),(6,1),(2,5),(5,2),(3,4),(4,3)\)…
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