AP EAMCET · Maths · Vector Algebra
\(\mathbf{a}\) and \(\mathbf{b}\) are unit vectors such that \(\mathbf{a}+2 \mathbf{b}\) is also a unit vector. If \(\theta\) is the angle between a and \(\mathbf{b}\), then \(\sin \theta+\cos ^3 \theta+\tan ^5 \theta\) is equal to
- A 3
- B 5
- C \(\frac{3}{\sqrt{2}}+1\)
- D -1
Answer & Solution
Correct Answer
(D) -1
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Given, }|\mathbf{a}|=|\mathbf{b}|=|\mathbf{a}+2 \mathbf{b}|=1 \\ & \qquad \begin{aligned}|\mathbf{a}+2 \mathbf{b}|^2 & =|\mathbf{a}|^2+4\left|\mathbf{b}^2\right|+4|\mathbf{a}||\mathbf{b}| \cos \theta \\ 1 & =1+4+4 \cos \theta \\ \cos \theta & =-1…
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