AP EAMCET · Maths · Definite Integration
\(\int_1^2 \tan ^{-1}\left(\frac{x}{x^2+1}\right)+\tan ^{-1}\left(\frac{x^2+1}{x}\right) d x=\)
- A \(\frac{\pi}{4}\)
- B \(\frac{3 \pi}{4}\)
- C \(\pi / 4\)
- D \(\pi / 2\)
Answer & Solution
Correct Answer
(D) \(\pi / 2\)
Step-by-step Solution
Detailed explanation
\(I=\int_1^2\left\{\tan ^{-1}\left(\frac{x}{x^2+1}\right)+\tan ^{-1}\left(\frac{x^2+1}{x}\right)\right\} d x\)…
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