AP EAMCET · Maths · Indefinite Integration
\(\int \frac{\sin ^6 x}{\cos ^8 x} d x=\)
- A \(\tan^7 x+c\)
- B \(\frac{\tan^7 x}{7}+c\)
- C \(\frac{\tan ^7 x}{3}+c\)
- D \(\sec ^7 x\)
Answer & Solution
Correct Answer
(B) \(\frac{\tan^7 x}{7}+c\)
Step-by-step Solution
Detailed explanation
\(\int \frac{\sin ^6 x}{\cos ^8 x} d x=\int \tan ^6 x \sec ^2 x d x=\frac{\tan ^7 x}{7}+c\).
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