AP EAMCET · Maths · Definite Integration
\(\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}}\left(\frac{x+\frac{\pi}{4}}{2-\cos 2 x}\right) d x\) is equal to
- A \(\frac{8 \pi \sqrt{3}}{5}\)
- B \(\frac{2 \pi \sqrt{3}}{9}\)
- C \(\frac{4 \pi^2 \sqrt{3}}{9}\)
- D \(\frac{\pi^2}{6 \sqrt{3}}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi^2}{6 \sqrt{3}}\)
Step-by-step Solution
Detailed explanation
Given, \(\mathrm{I}=\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{x+\frac{\pi}{4}}{2-\cos ^2 x} d x\) \(\mathrm{I}=\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{x+\frac{\pi}{4}}{2-\cos ^2 x} d x+\frac{\pi}{4} \int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{1}{2-\cos ^2 x} d x\) Let,…
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