AP EAMCET · Maths · Inverse Trigonometric Functions
\(2 \operatorname{coth} h^{-1}(4)+\sec h^{-1}\left(\frac{3}{5}\right)=\)
- A \(\log 5\)
- B \(2 \log 3\)
- C \(3 \log 2\)
- D \(\log \frac{5}{3}\)
Answer & Solution
Correct Answer
(A) \(\log 5\)
Step-by-step Solution
Detailed explanation
As \(\cot h^{-1}(x)=\frac{1}{2} \log \left(\frac{x+1}{x-1}\right)\) and \(\sec h^{-1}(x)=\log \left(\frac{1+\sqrt{1-x^2}}{x}\right)\) Now, \(2 \cot h^{-1}(4)+\sec h^{-1}\left(\frac{3}{5}\right)\)…
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