AP EAMCET · Maths · Trigonometric Ratios & Identities
\(\sin \frac{2 \pi}{5}+\sin \frac{4 \pi}{5}+\sin \frac{6 \pi}{5}+\sin \frac{8 \pi}{5}\) is equal to
- A 0
- B 1
- C \(\frac{\sqrt{2}}{2}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
\(\sin \frac{2 \pi}{5}+\sin \frac{4 \pi}{5}+\sin \frac{6 \pi}{5}+\sin \frac{8 \pi}{5}\) \(=\left(\sin \frac{2 \pi}{5}+\sin \frac{8 \pi}{5}\right)+\left(\sin \frac{4 \pi}{5}+\sin \frac{6 \pi}{5}\right)\)…
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