AP EAMCET · Maths · Indefinite Integration
\[
\int \frac{1}{(\sin x+\cos x+\sqrt{2} \sqrt{\sin 2 x})^2} d x=
\]
- A \(\frac{-(1+3 \sqrt{\tan x})}{\left(3+\tan ^2 x\right)^3}+C\)
- B \(\frac{-(1+3 \sqrt{\tan x})}{3(1+\sqrt{\tan x})^3}+C\)
- C \(\frac{-(1+\sqrt{\tan x})}{3(1+3 \sqrt{\tan x})^2}+C\)
- D \(\frac{1}{(1+3 \sqrt{\tan x})^3}+C\)
Answer & Solution
Correct Answer
(B) \(\frac{-(1+3 \sqrt{\tan x})}{3(1+\sqrt{\tan x})^3}+C\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { } \int \frac{1}{(\sin x+\cos x+\sqrt{2} \sqrt{\sin 2 x})^2 d x} \\ & \int \frac{1}{\left(\sqrt{\sin x}+\sqrt{\cos x)^4 d x}\right.}=\int \frac{\sec ^2 x}{(\sqrt{\tan x}+1)} d x \end{aligned} \] Let \(\tan x=t^2 \Rightarrow \sec ^2 x d x=2 t d t\)…
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