AP EAMCET · Maths · Definite Integration
\(\int_0^{\pi / 4} \frac{\cos ^2 x}{\cos ^2 x+4 \sin ^2 x} d x=\)
- A \(\frac{\pi}{2}-\frac{1}{3} \operatorname{Tan}^{-1} 2\)
- B \(-\frac{\pi}{4}-\frac{4}{3} \operatorname{Tan}^{-1} 2\)
- C \(\frac{\pi}{6}+\frac{2}{3} \operatorname{Tan}^{-1} 2\)
- D \(-\frac{\pi}{12}+\frac{2}{3} \operatorname{Tan}^{-1} 2\)
Answer & Solution
Correct Answer
(D) \(-\frac{\pi}{12}+\frac{2}{3} \operatorname{Tan}^{-1} 2\)
Step-by-step Solution
Detailed explanation
\(\int_0^{\pi / 4} \frac{\cos ^2 x}{\cos ^2 x+4 \sin ^2 x} d x = \int_0^{\pi / 4} \frac{1}{1+4 \tan ^2 x} d x\) Let \(t = \tan x \Rightarrow dt = \sec^2 x dx = (1+\tan^2 x) dx = (1+t^2) dx \Rightarrow dx = \frac{dt}{1+t^2}\) Limits: \(x=0 \Rightarrow t=0\),…
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