AP EAMCET · Chemistry · Solutions

When $36 g$ of a non-volatile, non-electrolytic solute have the empirical formula ${CH}_{2} O$ is dissolved in $1.2 kg$ of water, the solution freezes at $- 0.93 ° C$ . The molecular formula of the solute is ( $K_{f}$ of water $= 1.86 K kg {mol}^{- 1}$ )

A ${CH}_{2} O$
B $C_{2} H_{4} O_{2}$
C $C_{3} H_{6} O_{3}$
D $C_{4} H_{8} O_{4}$

Verified Solution

Answer & Solution

Correct Answer

(B) $C_{2} H_{4} O_{2}$

Step-by-step Solution

Detailed explanation

Given, Mass of the solute =36 g Mass of the solvent =1.2 kg ∆Tf= Depression in freezing point =0.93°C KfH2O=1.86 K kg mol-1 We know that, ∆Tf=Kf×m Molality,…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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When 36 g of a non-volatile, non-electrolytic solute have the empirical formula CH2O is dissolved in 1.2 kg of water, the solution freezes at -0.93°C. The molecular formula of the solute is (Kf of water =1.86 K kg mol-1)

Step-by-step Solution

When $36 g$ of a non-volatile, non-electrolytic solute have the empirical formula ${CH}_{2} O$ is dissolved in $1.2 kg$ of water, the solution freezes at $- 0.93 ° C$ . The molecular formula of the solute is ( $K_{f}$ of water $= 1.86 K kg {mol}^{- 1}$ )