AP EAMCET · Chemistry · Electrochemistry
What is the molar conductivity of \(\mathrm{CH}_3 \mathrm{CO}_2 \mathrm{H}\) at infinite dilution?
Given that,
\(\wedge_{\mathrm{m}}^{\mathrm{o}}\left(\mathrm{CH}_3 \mathrm{CO}_2\right)_2 \mathrm{Ba}=\mathrm{x}_1 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
\(\begin{aligned} & \wedge_{\mathrm{m}}^{\mathrm{o}}\left(\mathrm{BaCl}_2\right)=\mathrm{x}_2 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1} \\ & \wedge_{\mathrm{m}}^{\mathrm{o}}(\mathrm{HCl})=\mathrm{x}_3 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\end{aligned}\)
- A \(\frac{x_1-x_2}{2}+x_3\)
- B \(\frac{\mathrm{x}_1-\mathrm{x}_3}{2}+\mathrm{x}_2\)
- C \(\frac{x_2-x_3}{2}+x_1\)
- D \(x_1+x_3-x_2\)
Answer & Solution
Correct Answer
(A) \(\frac{x_1-x_2}{2}+x_3\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{CH}_3 \mathrm{COOH} \rightleftharpoons \mathrm{CH}_3 \mathrm{COO}^{-}+\mathrm{H}^{+} ; \mathrm{HCl} \rightarrow \mathrm{H}^{+}+\mathrm{Cl}^{-} \\ & \left(\mathrm{CH}_3 \mathrm{COO}\right)_2 \mathrm{Ba} \longrightarrow 2 \mathrm{CH}_3…
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