AP EAMCET · Chemistry · Electrochemistry
During the electrolysis of copper sulphate aqueous solution using copper electrode, the reaction takine place at the cathode is
- A \(\mathrm{Cu} \longrightarrow \mathrm{Cu}^{2+}(\mathrm{aq})+2 e^{-}\)
- B \(\mathrm{Cu}^{2+}(\mathrm{aq})+2 e^{-} \longrightarrow \mathrm{Cu}(\mathrm{s})\)
- C \(\mathrm{H}^{+}(\mathrm{aq})+\mathrm{e}^{-} \longrightarrow \frac{1}{2} \mathrm{H}_2(g)\)
- D \(\mathrm{SO}_4^{2-}(\mathrm{aq}) \longrightarrow \mathrm{SO}_3(g)+\frac{1}{2} \mathrm{O}_2(g)+2 e^{-}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{Cu}^{2+}(\mathrm{aq})+2 e^{-} \longrightarrow \mathrm{Cu}(\mathrm{s})\)
Step-by-step Solution
Detailed explanation
During the electrolysis of an aqueous solution of copper sulphate using copper electrodes, both \(\mathrm{Cu}^{2+}\) and \(\mathrm{H}^{+}\)ions move towards cathode, but the discharge potential of \(\mathrm{Cu}^{2+}\) ions is lower than that of \(\mathrm{H}^{+}\)ions, therefore…
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