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AP EAMCET · Chemistry · Chemical Equilibrium

Using the data provided, find the value of equilibrium constant for the following reaction at 298 K and 1 atm pressure. NO(g)+12O2( g)NO2( g)
ΔfH0NO(g)=90.4kJ.mol1 ΔfH0NO2(g)=32.48kJmol1 ΔS@298K=70.8JK1mol1 antilog(0.50)=3162

  1. A 3.162×104
  2. B 3.162×10-4
  3. C 3.162×106
  4. D 3.162×107
Verified Solution

Answer & Solution

Correct Answer

(C) 3.162×106

Step-by-step Solution

Detailed explanation

The given reaction is NO(g)+12O2( g)⇌NO2( g) The enthalpy of the above reaction given by the difference of enthalpies of reactant side and product side. Therefore,…