AP EAMCET · Chemistry · Structure of Atom

Two thin circular discs $A$ and $B$ of radii $2 cm$ and $4 cm$ are in a liquid at the same depth. $T_{A}$ is the thrust on $A$ and $T_{B}$ thrust on $B$ . Then $T_{A} : T_{B} =$

A $2 : 1$
B $1 : 2$
C $4 : 1$
D $1 : 4$

Verified Solution

Answer & Solution

Correct Answer

(D) $1 : 4$

Step-by-step Solution

Detailed explanation

Thrust force is given by Th=vsubρg volume=areaA×widtht⇒Th=Atρg Here width(t),density(ρ)ang g are same for both disc so Th∝A…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From AP EAMCET

Explore more questions on app

Two thin circular discs A and B of radii 2 cm and 4 cm are in a liquid at the same depth. TA is the thrust on A and TB thrust on B. Then TA:TB=

Step-by-step Solution

Two thin circular discs $A$ and $B$ of radii $2 cm$ and $4 cm$ are in a liquid at the same depth. $T_{A}$ is the thrust on $A$ and $T_{B}$ thrust on $B$ . Then $T_{A} : T_{B} =$