AP EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
To prepare \(\mathrm{XeF}_6 \cdot \mathrm{Xe}\) and \(\mathrm{F}_2\) are mixed at \(573 \mathrm{~K}\) and \(60-70\) bar in the ratio of
- A 20 : 1
- B 1: 5
- C 5 : 1
- D 1: 20
Answer & Solution
Correct Answer
(D) 1: 20
Step-by-step Solution
Detailed explanation
\(\underset{(1: 20)}{\mathrm{Xe}+\mathrm{F}_2} \frac{573 \mathrm{~K}}{60-70 \mathrm{bar}} \mathrm{XeF}_6\)
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