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AP EAMCET · Chemistry · Structure of Atom

The wavelength of electron in the first orbit of hydrogen atom is \(3.3 \times 10^{-10} \mathrm{~m}\). The kinetic energy of electron (in \(\mathrm{J}\) ) is
\(\left(\mathrm{h}=6.6 \times 10^{-34} \mathrm{Js}, \mathrm{m}_{\mathrm{e}}=9.0 \times 10^{-31} \mathrm{~kg}\right)\)

  1. A \(3.33 \times 10^{-17}\)
  2. B \(1.11 \times 10^{-18}\)
  3. C \(2.22 \times 10^{-18}\)
  4. D \(2.22 \times 10^{-17}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2.22 \times 10^{-18}\)

Step-by-step Solution

Detailed explanation

From de-Broglie's equation \(\mathrm{p}=\frac{\mathrm{h}}{\lambda}\) or, \(\mathrm{v}=\frac{\mathrm{h}}{\mathrm{m} \lambda}\) K.E. \(=\frac{1}{2} \mathrm{mv}^2=\frac{1}{2} \mathrm{~m} \cdot \frac{\mathrm{h}^2}{\mathrm{~m}^2\left(3.3 \times 10^{-10}\right)^2}\)…