AP EAMCET · Chemistry · Coordination Compounds
The spin only magnetic moment of \(\left[\mathrm{MnBr}_4\right]^{\mathrm{x}-}\) is \(5.9 \mathrm{BM}\). The geometry of the complex and \(\mathrm{x}\) respectively are
- A tetrahedral, 1
- B square planar, 1
- C square planar, 2
- D tetrahedral, 2
Answer & Solution
Correct Answer
(D) tetrahedral, 2
Step-by-step Solution
Detailed explanation
\(\mu_{\mathrm{s}}=\sqrt{\mathrm{n}(\mathrm{n}+2)}=5.9\) B. M. \(\Rightarrow \mu^2=\mathrm{n}(\mathrm{n}+2)=34.81 \Rightarrow \mathrm{n}=5\) Thus, \(\mathrm{Mn}\) will have five unpaired electrons so \(\mathrm{Mn}\) will be in +2 state with \(\mathrm{Br}^{-}\)being weak- field…
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