AP EAMCET · Chemistry · Surface Chemistry
The plot of \(\log \frac{x}{m}\) (y-axis) and \(\log p(x\)-axis) is a straight line inclined at an angle of \(45^{\circ}\). When the intercept, \(\mathrm{K}\) is 10 and pressure is \(0.3 \mathrm{~atm}\) the amount of solute in grams adsorbed per gram of adsorbent \((\log 3=\) \(0.4771) ?\)
- A \(30.0\)
- B \(2.0\)
- C \(3.0\)
- D \(20.0\)
Answer & Solution
Correct Answer
(C) \(3.0\)
Step-by-step Solution
Detailed explanation
According to Freundlich adsorption isotherm:- \(\log \frac{x}{m}=\frac{1}{n} \log p+\log k(y=m x+c)\) We have, \(\log \mathrm{k}=\log 10=1\) \(\log \mathrm{p}=\log (0.3)=-0.523\) \(\theta=45^{\circ} \text { so slope }=\frac{1}{n}=\tan \theta=\tan 45^{\circ}=1\) Thus,…
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