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AP EAMCET · Chemistry · Ionic Equilibrium

The \(\mathrm{pH}\) of \(0.01 \mathrm{M} \mathrm{BOH}\) solution is 10 . What is its degree of dissociation?
(Given \(\mathrm{K}_{\mathrm{b}}\) of \(\mathrm{BOH}\) is \(1 \times 10^{-6}\) )

  1. A \(10 \%\)
  2. B \(5 \%\)
  3. C \(2 \%\)
  4. D \(1 \%\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(10 \%\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \mathrm{BOH} \rightleftharpoons \mathrm{B}^{+}+\mathrm{OH}^{-} \\ & \mathrm{K}_{\mathrm{b}}=\frac{\left[\mathrm{B}^{+}\right]\left[\mathrm{OH}^{-}\right]}{[\mathrm{BOH}]}=1 \times 10^{-6} \\ & \mathrm{pH}=10 \Rightarrow \mathrm{pOH}=14-10=4 \\ &…

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