AP EAMCET · Chemistry · Chemical Equilibrium
The equilibrium constant at \(850 \mathrm{~K}\) for the reaction \(\mathrm{N}_2(g)+\mathrm{O}_2(g) \rightleftharpoons 2 \mathrm{NO}(g)\) is 0.5625 . The equilibrium concentration of \(\mathrm{NO}(g)\) is \(3.0 \times 10^{-3} \mathrm{M}\). If the equilibrium concentrations of \(\mathrm{N}_2(g)\) and \(\mathrm{O}_2(g)\) are equal, the concentrations of \(\mathrm{N}_2(g)\) in \(M\) is
- A \(4.0 \times 10^{-3}\)
- B \(4.0 \times 10^{-2}\)
- C \(1.6 \times 10^{-3}\)
- D \(3.0 \times 10^{-3}\)
Answer & Solution
Correct Answer
(A) \(4.0 \times 10^{-3}\)
Step-by-step Solution
Detailed explanation
Given, \(\mathrm{N}_2(g)+\mathrm{O}_2(g) \rightleftharpoons 2 \mathrm{NO}(g)\) i.e. equilibrium constant, \(K_C=0.5625\) Equilibrium concentration of \([\mathrm{NO}]=3 \times 10^{-3} \mathrm{M}\)…
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