AP EAMCET · Chemistry · Solutions
\(2 \mathrm{~g}\) of a non-electrolyte solute (molar mass is \(500 \mathrm{~g} \mathrm{~mol}^{-1}\) ) was dissolved in \(57.3 \mathrm{~g}\) of xylene. If the freezing point depression constant \(K_f\) of xylene is \(4.3 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\). Then, the depression in freezing point of xylene is..........
- A \(57.3 \mathrm{~K}\)
- B \(0.3 \mathrm{~K}\)
- C \(4.3 \mathrm{~K}\)
- D \(0.002 \mathrm{~K}\)
Answer & Solution
Correct Answer
(B) \(0.3 \mathrm{~K}\)
Step-by-step Solution
Detailed explanation
\(\Delta T_f=K_f \times \frac{w_1 \times 1000}{w_2 \times m_1}\) \(\begin{aligned} & w_1=\text { weight of solute } \\ & w_2=\text { weight of solvent } \\ & m_1=\text { molar mass of solute } \\ & K_f=4.3 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\end{aligned}\) Now,…
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