AP EAMCET · Maths · Straight Lines
The equation of bisectors of the angle between the lines given by \(3 x^2+5 x y+4 y^2=0\) is
- A \(x^2-y^2-\frac{2}{5} x y=0\)
- B \(x^2-y^2+\frac{2}{5} x y=0\)
- C \(x^2-y^2-\frac{1}{5} x y=0\)
- D \(x^2-y^2+\frac{1}{5} x y=0\)
Answer & Solution
Correct Answer
(B) \(x^2-y^2+\frac{2}{5} x y=0\)
Step-by-step Solution
Detailed explanation
The equation of the bisectors of the angle between the line \(3 x^2+5 x y+4 y^2=0\) is \(\frac{x^2-y^2}{3-4}=\frac{x y}{\frac{5}{2}}\) or \(\quad x^2-y^2=-\frac{2}{5} x y\) i.e. \(x^2-y^2+\frac{2}{5} x y=0\)
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