AP EAMCET · Chemistry · Solutions
The degree of ionization of \(0.10 \mathrm{M}\) lactic acid is \(4.0 \%\)
The value of \(K_c\) is
- A \(1.66 \times 10^{-5}\)
- B \(1.66 \times 10^{-4}\)
- C \(1.66 \times 10^{-3}\)
- D \(1.66 \times 10^{-2}\)
Answer & Solution
Correct Answer
(B) \(1.66 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
\(\%\) dissociation \(=4 \%\) degree of dissociation \((\alpha)=\frac{4}{100}=0.04\) For lactic acid \[ \mathrm{CH}_3 \mathrm{CH}(\mathrm{OH}) \mathrm{COOH} \rightleftharpoons \mathrm{CH}_3 \mathrm{CH}(\mathrm{OH}) \mathrm{COO}^{-}+\mathrm{H}^{+} \] Initial concentration…
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