AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure

The correct order of electronegativity of carbon in various hybridization states:

A $s p < s p^{2} < s p^{3}$
B $s p > s p^{2} > s p^{3}$
C $s p^{2} > s p < s p^{3}$
D $s p = s p^{2} < s p^{3}$

Verified Solution

Answer & Solution

Correct Answer

(B) $s p > s p^{2} > s p^{3}$

Step-by-step Solution

Detailed explanation

We know that more will be %s character in the hybrid orbitals more will be the tendency of the orbitals to attract the shared paired of electrons towards itself and consequently more will be the electronegativity. Now, the %s character in different hybridisation states of carbon…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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