AP EAMCET · Chemistry · Structure of Atom
If the radius of electron in the excited state of \(\mathrm{He}^{+}\)is \(0.4232 \mathrm{~nm}\), the energy of electron in that excited state in \(\mathrm{J}\) is :
(The radius and energy of electron in the first orbit of hydrogen atom are \(52.9 \mathrm{pm}\) and \(-2.18 \times 10^{-18} \mathrm{~J}\) respectively)
- A \(-5.45 \times 10^{-17}\)
- B \(-5.45 \times 10^{-19}\)
- C \(5.45 \times 10^{18}\)
- D \(5.45 \times 10^{-18}\)
Answer & Solution
Correct Answer
(B) \(-5.45 \times 10^{-19}\)
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