AP EAMCET · Chemistry · Electrochemistry
The cell potential for the following cell notation is approximately
\(\begin{aligned} & \mathrm{M}(\mathrm{s})\left|\mathrm{M}^{3+}(\mathrm{aq}, 0.01 \mathrm{M}) \| \mathrm{N}^{2+}(\mathrm{aq}, 0.1 \mathrm{M})\right| \mathrm{N}(\mathrm{s}) \\ & \mathrm{E}_{\mathrm{M}^{3+} / \mathrm{M}}^0=0.6 \mathrm{~V} \text { and } \mathrm{E}_{\mathrm{N}^{2+} / \mathrm{N}}^0=0.1 \mathrm{~V}\end{aligned}\)
- A \(0.51 \mathrm{~V}\)
- B \(1.5 \mathrm{~V}\)
- C \(2.0 \mathrm{~V}\)
- D \(2.5 \mathrm{~V}\)
Answer & Solution
Correct Answer
(A) \(0.51 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
\(\left(\mathrm{M} \rightarrow \mathrm{M}^{3+}+3 \mathrm{e}\right) \times 2 ;\left(\mathrm{N}^{2+}+2 \mathrm{e} \rightarrow \mathrm{N}\right) \times 3\) Overall reaction…
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