AP EAMCET · Chemistry · Thermodynamics (C)
If the work done by \(2 \mathrm{~mol}\) of an ideal gas during isothermal reversible expansion from \(5 \mathrm{~L}\) to \(50 \mathrm{~L}\) is \(-189.1 \mathrm{~L}\) atm at constant pressure, the temperature of the gas (in \({ }^{\circ} \mathrm{C}\) ) is
- A \(500\)
- B \(227\)
- C \(327\)
- D \(127\)
Answer & Solution
Correct Answer
(B) \(227\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{W}_{\text {rev }}=-2.303 \mathrm{nRT} \log \left(\frac{\mathrm{P}_1}{\mathrm{P}_2}\right) \\ & =-2.303 \mathrm{nRT} \log \left(\frac{\mathrm{V}_2}{\mathrm{~V}_1}\right) \end{aligned}\) We have,…
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