AP EAMCET · Chemistry · Structure of Atom
If the wavelength of the first line in Balmer series is 656 nm, then the wavelength of its second line and limiting line respectively are
- A 485.9 nm and 434 nm
- B 485.9 nm and 364.4 nm
- C 715 nm and 434 nm
- D 608 nm and 415.2 nm
Answer & Solution
Correct Answer
(B) 485.9 nm and 364.4 nm
Step-by-step Solution
Detailed explanation
According to H-spectrum; Rydberg formula \(\Rightarrow \frac{1}{\lambda}=R_{\mathrm{H}}\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)\) For first line, \(n_1=2, n_2=3\) (Balmer series) \(\lambda=656 \mathrm{~nm}\)…
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