AP EAMCET · Chemistry · Structure of Atom
If the position of the electron was measured with an accuracy of +0.002 nm . the uncertainty in the momentum of it would be (in \(\left.\mathrm{kg} \mathrm{ms}^{-1}\right)\left(\mathrm{h}=6.626 \times 10^{-34} \mathrm{~J} \mathrm{~s}\right)\)
- A \(2.637 \times 10^{-23}\)
- B \(2.637 \times 10^{-24}\)
- C \(8.283 \times 10^{-23}\)
- D \(8.283 \times 10^{-24}\)
Answer & Solution
Correct Answer
(A) \(2.637 \times 10^{-23}\)
Step-by-step Solution
Detailed explanation
Heisenberg uncertainty principle, \(\Delta x \cdot \Delta p=\frac{h}{4 \pi}\)…
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