AP EAMCET · Chemistry · Structure of Atom
If the maximum kinetic energy of photoelectrons ejected from a metal surface when it is irradiated with a radiation of frequency \(4 \times 10^{14} \mathrm{~s}^{-1}\) is \(6.63 \times 10^{-20} \mathrm{~J}\), then the threshold frequency of the metal is
- A \(2 \times 10^{14} \mathrm{~s}^{-1}\)
- B \(1 \times 10^{14} \mathrm{~s}^{-1}\)
- C \(3 \times 10^{14} \mathrm{~s}^{-1}\)
- D \(1 \times 10^{-14} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(C) \(3 \times 10^{14} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
The threshold energy for production of a particle is the minimum K.E., a pair of travelling particles must have when they collide.…
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