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AP EAMCET · Chemistry · Solid State

If AgCl is doped with \(1 \times 10^{-4}\) mole percent of \(\mathrm{CdCl}_2\), the number of cation vacancies ( \(\mathrm{in}\) \(\mathrm{mol}^{-1}\) ) is

  1. A \(6.023 \times 10^{19}\)
  2. B \(6.023 \times 10^{21}\)
  3. C \(6.023 \times 10^{17}\)
  4. D \(6.023 \times 10^{23}\)
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Answer & Solution

Correct Answer

(C) \(6.023 \times 10^{17}\)

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