AP EAMCET · Chemistry · Solid State

If \(0.5 \mathrm{~mol}\) of a metal forms hexagonal close packed structure, the total number of voids, and tetrahedral voids respectively in mol are

A \(1.5,1.0\)
B \(1.0,0.5\)
C \(1.0,1.5\)
D \(0.5,1.0\)

Verified Solution

Answer & Solution

Correct Answer

(A) \(1.5,1.0\)

Step-by-step Solution

Detailed explanation

Number of moles of metal in close packed structure \(=0.5 \mathrm{~mol}\) No. of atoms in 1 mole of mole \(=N_A\) \(\therefore\) Number of atoms in \(0.5 \mathrm{~mol}\) of metal \(=0.5 \times 6.022 \times 10^{23}=3.011 \times 10^{23}\) Also, number of tetrahedral voids…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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