AP EAMCET · Chemistry · Chemical Kinetics
For a reaction, the graph of \(\ln \mathrm{k}\) (on y -axis) and \(1 / \mathrm{T}\) (on x -axis) is a straight line with a slope \(-2 \times 10^4 \mathrm{~K}\). The activation energy of the reaction (in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) is \(\left(\mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)\)
- A \(332\)
- B \(432\)
- C \(166\)
- D \(216\)
Answer & Solution
Correct Answer
(C) \(166\)
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