AP EAMCET · Chemistry · p Block Elements (Group 13 & 14)
Consider the following reaction \(\mathrm{BCl}_3+\mathrm{NH}_3 \longrightarrow \mathrm{BCl}_3 \cdot \mathrm{NH}_3\)
The geometries of \(\mathrm{BCl}_3\) and \(\mathrm{BCl}_3 \cdot \mathrm{NH}_3\) respectively are
- A trigonal planar and tetrahedral
- B tetrahedral and square planar
- C tetrahedral and trigonal bipyramidal
- D square planar and trigonal pyramidal
Answer & Solution
Correct Answer
(A) trigonal planar and tetrahedral
Step-by-step Solution
Detailed explanation
The molecular geometry of \(\mathrm{BCl}_3\) is trigonal planar. In \(\mathrm{BCl}_3 \cdot \mathrm{NH}_3\), the central atom \(\mathrm{B}\) has 6 valence electrons that makes it an electron deficient molecule. \(\mathrm{BCl}_3\) acts as a Lewis acid as it needs 2 electrons to…
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