AP EAMCET · Chemistry · d and f Block Elements
Calculated magnetic moment value for \(\mathrm{Fe}^{2+}\) ion in \(\mathrm{BM}\) is
- A \(3.87\)
- B \(4.90\)
- C \(2.84\)
- D \(1.73\)
Answer & Solution
Correct Answer
(B) \(4.90\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Fe}^{2+}\left(\mathrm{d}^6\right):\) Unpaired electrons \((\mathrm{n})=4\) \(\therefore \quad \mu_{\text {s.o. }}=\sqrt{4(4+2)}=2 \sqrt{6}=4.89 \simeq 4.90 \mathrm{BM}\)
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