AP EAMCET · Chemistry · Electrochemistry
Calculate \(\Delta G^{\circ}\) for the following cell reaction.
\(\begin{aligned} & \mathrm{Zn}(\mathrm{s})+\mathrm{Ag}_2 \mathrm{O}(\mathrm{s})+\mathrm{H}_2 \mathrm{O}(l) \longrightarrow \\ & \mathrm{Zn}^{2+}(\mathrm{aq})+2 \mathrm{Ag}(\mathrm{s})+2^{-} \mathrm{OH}(\mathrm{aq}) \\ & E_{\mathrm{Ag}^{+} / \mathrm{Ag}}^{\circ}=+0.80 \mathrm{~V} \text { and } E_{\mathrm{Zn}^{2+} / \mathrm{Zn}}^{\circ}=-0.76 \mathrm{~V}\end{aligned}\)
- A \(-305 \mathrm{~kJ} / \mathrm{mol}\)
- B \(-301 \mathrm{~kJ} / \mathrm{mol}\)
- C \(305 \mathrm{~kJ} / \mathrm{mol}\)
- D \(301 \mathrm{~kJ} / \mathrm{mol}\)
Answer & Solution
Correct Answer
(B) \(-301 \mathrm{~kJ} / \mathrm{mol}\)
Step-by-step Solution
Detailed explanation
\(\quad E_{\text {cell }}^{\circ}=E^{\circ}{ }_C-E_A^{\circ}=0.80-(-0.76)=1.56 \mathrm{~V}\) From the equation \(\Delta G^{\circ}=-n F E^{\circ}\)…
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