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AP EAMCET · Chemistry · Solutions

At \(T(\mathrm{~K})\), the vapour pressures of pure liquids \(A\) and \(B\) are \(100 \mathrm{~mm}\) and \(160 \mathrm{~mm}\) respectively. An ideal solution is formed by mixing 2 moles of \(A\) and 3 moles of \(B\) at the same temperature. The mole fraction of \(A\) and \(B\) in the vapour state respectively are

  1. A \(0.706,0.294\)
  2. B \(0.294,0.706\)
  3. C \(0.40,0.60\)
  4. D \(0.60,0.40\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(0.294,0.706\)

Step-by-step Solution

Detailed explanation

Key Idea Vapour pressure of solution, \(p_{\text {total }}=p_A+p_{B^{\prime}}=\chi_A p_A^{\circ}+\chi_B p_B^{\circ} \quad\left[\because p_A=\chi_A p_A^{\circ}\right]\) Also vapour pressure of component \(1, p_1=y_1 p_{\text {total }}\) where \(y\), is the mole fraction of…