AP EAMCET · Chemistry · Ionic Equilibrium
At \(\mathrm{T}(\mathrm{K})\), the solubility product of AgBr is \(4 \times 10^{-13}\). What is its solubility in 0.1 M KBr solution?
- A \(2 \times 10^{-6} \mathrm{M}\)
- B \(4 \times 10^{-10} \mathrm{M}\)
- C \(4 \times 10^{-12} \mathrm{M}\)
- D \(4 \times 10^{-14} \mathrm{M}\)
Answer & Solution
Correct Answer
(C) \(4 \times 10^{-12} \mathrm{M}\)
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