AP EAMCET · Chemistry · States of Matter
At a given temperature, the density of an ideal gas is proportional to
(\(\mathrm{P}=\) pressure of ideal gas)
- A \(\frac{1}{\mathrm{P}}\)
- B \(\mathrm{P}\)
- C \(\mathrm{P}^2\)
- D \(\sqrt{\mathrm{P}}\).
Answer & Solution
Correct Answer
(B) \(\mathrm{P}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{d}=\frac{\mathrm{m}}{\mathrm{V}}=\frac{(\mathrm{n} \times \mathrm{M})}{\frac{\mathrm{nRT}}{\mathrm{P}}}=\frac{\mathrm{PM}}{\mathrm{RT}}=\left(\frac{\mathrm{M}}{\mathrm{RT}}\right) \mathrm{P}\) Thus, \(\mathrm{d} \alpha \mathrm{P}\)
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