AP EAMCET · Chemistry · Structure of Atom
The ratio of de-Broglie wavelength of two particles \(A\) and \(B\) is \(2: 1\). If the velocities of \(A\) and \(B\) are \(0.05 \mathrm{~ms}^{-1}\) and \(0.02 \mathrm{~ms}^{-1}\), respectively, then the ratio of their masses \(m_A: m_B\) must be
- A \(5: 1\)
- B \(10: 1\)
- C \(1: 5\)
- D \(1: 8\)
Answer & Solution
Correct Answer
(C) \(1: 5\)
Step-by-step Solution
Detailed explanation
According to de-Broglie's wavelength, \(\lambda=\frac{h}{m v}\) Now, de-Broglie's wavelength of particle \(A\) is \[ \lambda_A=\frac{h}{m_A v_A} \] Similarly, de-Broglie's wavelength of particle \(B\) is \[ \lambda_B=\frac{h}{m_B v_B} \] \(\therefore\) Ratio of de-Broglie…
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